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SQL Server Forum / Other Technologies / Full-Text Search / January 2007Search string with percent sign %
We have a database full of grocery items that we're trying to search. When I search for "*1%*" it seems that the percent sign is ignored and I get back all the rows that match "*1*" (which is A LOT). Is there anyway I can tell full-text search not to discard the percent sign and treat "1%" as a word? i should mention this is Sql 2000 on Win2k > We have a database full of grocery items that we're trying to search. When I > search for "*1%*" it seems that the percent sign is ignored and I get back > all the rows that match "*1*" (which is A LOT). Is there anyway I can tell > full-text search not to discard the percent sign and treat "1%" as a word? Hello John S., Try LIKE '*1[%]*' This is explained in BOL Simon Sabin SQL Server MVP http://sqlblogcasts.com/blogs/simons > i should mention this is Sql 2000 on Win2k > [quoted text clipped - 3 lines] >> there anyway I can tell full-text search not to discard the percent >> sign and treat "1%" as a word? Hi Simon, I also forgot to mention that I need to do this with CONTAINSTABLE. > Hello John S., > [quoted text clipped - 13 lines] > >> there anyway I can tell full-text search not to discard the percent > >> sign and treat "1%" as a word? Hello John S., I don't think you can as % is considered an ignored character. In addition you can't do searches with a preceeding wild card "*simon" is not valid whilst "simon*" is. Simon Sabin SQL Server MVP http://sqlblogcasts.com/blogs/simons > Hi Simon, > I also forgot to mention that I need to do this with CONTAINSTABLE. [quoted text clipped - 15 lines] >>>> LOT). Is there anyway I can tell full-text search not to discard >>>> the percent sign and treat "1%" as a word? |
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